10m^2-3m-7=-6

Solution for 10m^2-3m-7=-6 equation:

10m^2-3m-7=-6

We move all terms to the left:

10m^2-3m-7-(-6)=0

We add all the numbers together, and all the variables

10m^2-3m-1=0

a = 10; b = -3; c = -1;
Δ = b2-4ac
Δ = -32-4·10·(-1)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-7}{2*10}=\frac{-4}{20}
=-1/5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+7}{2*10}=\frac{10}{20}
=1/2
$